Zaujali ma slová prastarých Číňanov a múdrosť ich dynastií, zneli asi takto ^^^ [...] Read more
Ľudová múdrosť:
Tak čo? Dáte otázečku z tretieho na gympli? Obrázok:
dnes sme diskutovali s prof, kde budú svietiť žiarovky menej: já som to riešil klasickým kirchhoffovým zákonom >+ prúd sa rozteká v uzle na 3 menšie, keďže I=I1++I3, kde I1..3<I, teda VĽAVO [...] Read more
Story: Does Fermat prove Einstein can't bend time space more than gamma coefficient? Picture & proof:
Interesting finding: if you curve time space in these ratios it is L=L_0* gamma=sqrt(1-1.75^2/3^2)=0.6 =>4/6=2/3 and ratio n^x=xn preserves same gamma == cca 2/3 = 1.75/0.03 is 4/6, my new story [...] Read more
Ták koľko bude konštanta C v tomto vtipe? Poďme počítať:
-sinx +c1 --sinx+c1 = 1/4(-sinx +c2 + sinx +c2); 2c1=0.5c2; => https://www.desmos.com/calculator/dnymopsvnc => c1=c2 =>0 => 0+0=0 [...] Read more
Á neviem... Kreativita na tému Windows 365 v oblaku:
^^^ [...] Read more
Samo vysvetľujúce :D Takto to cítim:
^^^ [...] Read more
Story: My ideas on parity charge violation in 3 meson systems in contradicition to 2 meson systems, picture:
Yesterday, at the annual Rencontres de Moriond conference taking place in La Thuile, Italy, the LHCb collaboration at CERN reported a new milestone in our understanding of the subtle yet profound [...] Read more
They asked me about kyborg 1 metamorph guess up. In a minute it spits up this computation:
kyborg 1 metamorph's guess up? derivatives of (x+1)x^2 ic cca pi*x^2, ommiting pi: 81-16 as squares = 64 both sides of tangents, if tangent is mutual it gives 100% so 64+?=100, result is 64+36=100; [...] Read more
All right GROK gave me a cold shower, there is no win according to him: revised algorithm:
Grok says many numbers are under Gaussian curve, but in the third from borders of green only 2 numbers to bet in ;) So can we understand this as 5 nums under red or just 2 nums between greens? Let's [...] Read more
Spúšťam metamorf: Čo keby some pomery odhadli na 2 riadky? História sa opakuje, toto sme už nekonvenčne počítali:
sqrt(2)/[sqrt(2)-0.5]:[sqrt(2)-0.5]=1.692 => 100%
1% is 1:100 => 0.1692 => 0.17=a
^^^ porovnaním tangent a uhlopriečok dostávame riešenie odhadom na 2 riadky ^^^ Vypínam metamorf :) Ale toto [...] Read more